good at math: Puzzles for all times Solutions

Showing posts with label Puzzles for all times Solutions. Show all posts

Friday, January 17, 2020

Recreational Puzzles For All

1. How many people must last at that spot if all but 2 are named Ishan, all but 2 are named Kartikey, in addition to all but 2 are named Anmay?

Answer 3

2. Mohini said to Kamla, “the pose out of seconds inward a twenty-four lx minutes menstruum is to a greater extent than than the pose out hours inward 10 years.” I she right?

Answer No, inward a twenty-four lx minutes menstruum no. of seconds = lx x lx x 24 = 86,400 seconds in addition to inward 10 years, no. of hours = 10 x 365 x 24 = 87, 600 years.

3. Using the digits 1 to 9, brand 3 3-digit numbers. The 2d pose out is twice the first. The 3rd pose out is 3 times the first. The outset pose out begins alongside 3.

Answer: 327, 654, 981

4. An emmet has half dozen legs, a spider has 8 legs in addition to a mouse has 4 legs.In a zoo, a human being counted 612 legs which came from an equal pose out of each of these animals. Identify how many animals at that spot are inward the zoo?

Answer: 612 divided past times (6 + 8 + 4)= 34

5. How many times nosotros tin hand the sack subtract 4 from 24?

Answer: Only 1 time. (After subtracting 4 from 24 it becomes 20)

6. If 3+2+5 = 153030

9+2+4 = 364872... 8+4+3 = 2439965+4+5 = 2550100then, 7+2+5 = ..............

Answer: 355070

7. If Rahul climbs v stairs inward 1 twenty-four lx minutes menstruum in addition to comes dorsum 4 steps downward the same twenty-four lx minutes menstruum thus inward how many days he volition accomplish the 20^th stair?

Answer: sixteen days because inward fifteen days he volition accomplish the 15^th stair in addition to on 16^th twenty-four lx minutes menstruum he volition climb v steps in addition to accomplish the 20^th stair.

8. 8 monkeys receive got 8 minutes to consume 8 bananas. How many minutes would it receive got 2 monkeys to consume 2 bananas?

Answer: 8

9. What numbers volition come upwards side past times side inward this sequence:

12, 13, 15, 17, 111, 113, 117, 119, 123, ... , ...

Answer: 129, 131 (Prime numbers preceded past times 1)

10. Using 8 eights in addition to improver only, tin hand the sack you lot brand 1000?

Answer 888 + 88 + 8 + 8 + 8 = 1000

12 Pebbles Puzzle Solution

Puzzle

Solution:

Number the pebbles 1 to 12

For the showtime weighing allow us set on the left pan pebbles

1,2,3,4 as well as on the correct pan pebbles 5,6,7,8

There are 2 possibilities. Either they balance, or they don't.

Case 1:

If they balance, as well as then the pebble to survive constitute is inwards the grouping 9,10,11,12.

In our moment weighing nosotros would set 1,2 inwards the left pan as well as 9,10 on the right. If these ease as well as then the pebble to survive constitute is either xi or 12.

Weigh pebble 1 against 11. If they balance, the required pebble is set out 12. If they produce non balance, as well as then xi is the required pebble.

If 1,2 vs 9,10 produce non balance, as well as then the required pebble is either ix or 10.

Again, weigh 1 against 9. If they balance, the required pebble is set out

10, otherwise it is set out 9.

Case 2:

if the showtime weighing 1,2,3,4 vs 5,6,7,8 does non balance?

Then whatever ane of these pebbles could survive the required pebble. Now, inwards fellowship to proceed, nosotros must maintain rails of which side is heavy for each of the

following weighings.

Suppose that 5,6,7,8 is the heavy side. We instantly weigh 1,5,6 against

2,7,8. If they balance, as well as then the required pebble is either three or 4.

Weigh four against 9, a known bad pebble. If they ease as well as then the required

pebble is 3, otherwise it is 4.

Now, if 1,5,6 vs 2,7,8 does non balance, as well as 2,7,8 is the heavy side,

then either seven or eight is a required, heavy pebble, or 1 is a required, lite pebble.

For the 3rd weighing, weigh seven against 8. Whichever side is heavy is

the required pebble. If they balance, as well as then 1 is the required pebble. Should the weighing of 1,5, half dozen vs 2,7,8 demo 1,5,6 to survive the heavy side, as well as then

either five or half dozen is a required heavy pebble or 2 is a lite required pebble. Weigh five against 6. The heavier ane is the required pebble. If they balance, as well as then 2 is a required lite pebble.

Milkman Puzzle Occupation Solution

Puzzle

Solution Transfer the milk from ane container to another...
8 0 0
3 five 0
3 ii 3
6 ii 0
6 0 2
1 five 2
1 iv 3
4 iv 0

Using Digits I To Ix Occupation Solution

Problem

Solution
There are many solutions:
1+2+3-4+5+6+78+9 = 100
1+23-4+5+6+78-9 = 100
1+2+34-5+67-8-9 = 100
123+4-5+67-89= 100
123+45-67+8-9 = 100
12+3-4+5+67+8+9 = 100
123-4-5-6-7+8-9 = 100
12-3-4+5-6+7+89 = 100
123-45-67+89 = 100
12+3+4+5-6-7+89 = 100
1+23-4+56+7+8+9 = 100

Thursday, January 16, 2020

4 Weights Work Solution

Problem

Using digits 1, 3, 9, 27 and symbols + or -, nosotros tin croak xl inwards the next way

1 = 1

2= 3-1

3=3

4= 3+1

5= 9- (3+1)

6 = ix – 3

7 = 9+1-3

8 = 9-1

9=9

10= 9+1

11= 9+3-1

12= 9+3

13= 9+3+1

14= 27 – (9+3+1)

15= 27- (9+3)

16= 27+1-(9+3)

17= 27- (9+1)

18= 27-9

19= 27+1-9

20= 27+3- (9+1)

21= 27+3- 9

22= 27+1+3-9

23= 27- (3+1)

24= 27-3

25= 27+1-3

26= 27-1

27= 27

28=27+1

29= 27+3-1

30= 27+3

31= 27+3+1

32= 27+9- (3+1)

33= 27+9-3

34= 27+9+1- 3

35= 27+9-1

36= 27+9

37= 27+9+1

38= 27+9+3-1

39= 3+9+27

40= 1+3+9+27

68 Coins Occupation Solution

Arranged 64 coins of same radii, r cm each, inward a 16r x xvi r space. Can y'all conform four to a greater extent than coins inward the same space? How?

Solution

Thursday, November 7, 2019